CONCEPT OF TIME,DISTANCE AND SHILDING
INTRODUCTION
Any work involving ionising
radiations may entail some potential hazard. Based on ICRP's system of Dose
Limitation, it is essential that the doses are kept as low as reasonably
achievable (ALARA).
• A knowledge of the nature and the
degree of the potential hazard will help to take appropriate control measures.
• In tele gamma unit In the ON position, the source is
adequately shielded except for the primary beam.
• In the case of X-ray machines,
radiation is emitted only during the time when the unit is energized.
Radiation
hazard may be broadly classified under
• internal hazard
• external hazard.
INTERNAL HAZARD
• Internal hazard arises due to actual
entry of radioactive material into the living organism.
The main
routes of intake are:
- Inhalation of contaminated air.
- Ingestion of contaminated food
and water.
- Entry of radionuclide directly into the blood stream, e.g., through open wound.
EXTERNAL HAZARD
• External hazard is caused when the
source of radiation is outside the body,
• e.g. X-rays and sealed radioactive sources.
• From external point of view, X-rays and gamma
rays are most hazardous on account of their higher penetrating power, beta rays
next and lastly the alpha particles.
• Hazard evaluation is necessary in
order to take control measures in radiation areas.
• The evaluation of radiation hazard starts at
the design stage of the radiation equipment.
• Under the present regulations, it is the duty
of the manufacturer to ensure that the equipment meets the stipulated radiation
safety standards.
• Similarly, the user of radiation
sources is required to ensure safety for patients, personnel and public.
• It is essential to evaluate the
hazard likely to arise, under normal working conditions, as also under
potential accident conditions (e.g., fire, explosion).
TIME, DISTANCE AND SHIELDING
• Three basic fundamental factors by
which external exposure to radiation can be controlled are time, distance and
shielding.
A)
TIME
• For a given shielding and distance
of source, the exposure from a source at a point will be directly proportional
to the time during which the exposure is `ON’.
LESSER THE TIME OF OPERATION, LESSER
WILL BE THE RADIATION DOSE
• The exposure rate from a telecobalt
source is 200 R per minute at 1 meter, what are the exposure in (a) 15 sec.,
(b) 3 min, and (c) 1 hour?
For
15 Sec.
Convert seconds to minutes 15 sec=60/15=0.25 min.
formula- Exposure=Exposure Rate×Time
=200×0.25 =50 R(ans.
b) for 3 min.
formula-
Exposure=Exposure Rate×Time
=200×3=600 R(ans.)
(c) Exposure for 1 hour
Convert hour to minutes- 1 hr=60 min
formula-
Exposure=Exposure Rate×Time
=200×60=12000 R(ans.)
The exposure increases linearly
with time.
Double the time → double the dose.
2. The exposure rate from a source
at a point where the engineers are doing servicing is 120 mR/hr. On a average
for how much time can the engineer work at this point without exceeding the
equivalent dose limits?
Exposure rate = 2 mR/min.
Exposure allowed/day = 8 mR.
• time/day = 8/2 = 4 min.
B) DISTANCE
• The exposure rate at any point from
a source of X or gamma rays varies inversely as the square of the distance of
the point from the source (inverse square law).
• LARGER THE DISTANCE, LESSER WILL BE
THE RADIATION DOSE
C) SHIELDING
• When maximum distance and minimum
time do not ensure an acceptably low radiation dose, adequate shielding must be
provided so that the radiation beam will be sufficiently attenuated.
• The exposure rate from a source of X
or gamma rays decreases exponentially with the thickness of the shielding
material interposed between the source and the point of interest.
• If I (e.g. R/min.) is the intensity
of the radiation at a point without shielding and I is the intensity when a
thickness of the material is interposed, then
REMEMBER
1. Time
a) Lower the time of exposure, lower
the dose to personnel.
b) Hence
other things remaining the same, the exposure time must be kept to the minimum
possible to ensure minimum dose.
Therefore
the radiation source must be `ON' for the minimum time required.
2. Distancе
a) Larger
the distance from the source, lesser the radiation dose.
b)
Hence, keep as far away as possible from the radiation source.
3. Shielding
a) Larger the shield thickness, lower, the
exposure rate.
b) Hence make use of as much shielding as
feasible.
4. The
measured output of a telecobalt machine is 200 RMM. What will be the exposure
rate at 1 metre if lead sheets of thickness 6 cm are interposed between the
unit and the detector.
6 cm of Pb
= 5 HVTs
• The exposure rate from a Cs-137
source at a point is 120 mR/h. How much lead should be interposed between the
source and the point so that exposure level could be brought down to 0.25 mR/hr
at this place (HVT of Pb = 0.6 cm)








